If \( A(3,1,-1), B\!\left(\frac{5}{3},\frac{7}{3},\frac{1}{3}\right) \), \( C(2,2,1) \) and \( D\!\left(\frac{10}{3},\frac{2}{3},-\frac{1}{3}\right) \) are the vertices of a quadrilateral \( ABCD \), then its area is:
\( \dfrac{5\sqrt{2}}{3} \)
\( \dfrac{2\sqrt{2}}{3} \)
\( 2\sqrt{2} \)
\( \dfrac{4\sqrt{2}}{3} \)