Figure shows a rod \( AB \), which is bent in a \( 120^\circ \) circular arc of radius \( R \). A charge \( (-Q) \) is uniformly distributed over rod \( AB \). What is the electric field \( \vec{E} \) at the centre of curvature \( O \)?
\( \dfrac{3\sqrt{3}\,Q}{8\pi \epsilon_0 R^2}\,(\hat{i}) \)
\( \dfrac{3\sqrt{3}\,Q}{16\pi^2 \epsilon_0 R^2}\,(\hat{i}) \)
\( \dfrac{3\sqrt{3}\,Q}{8\pi^2 \epsilon_0 R^2}\,(-\hat{i}) \)
\( \dfrac{3\sqrt{3}\,Q}{8\pi^2 \epsilon_0 R^2}\,(\hat{i}) \)