Let \( x_1, x_2, \ldots, x_{10} \) be ten observations such that \( \displaystyle \sum_{i=1}^{10} (x_i-2)=30 \), \( \displaystyle \sum_{i=1}^{10} (x_i-\beta)^2=98 \), \( \beta>2 \), and their variance is \( \frac{4}{5} \). If \( \mu \) and \( \sigma^2 \) are respectively the mean and the variance of \( 2(x_1-1)+4\beta \), \( 2(x_2-1)+4\beta \), \( \ldots \), \( 2(x_{10}-1)+4\beta \), then \( \frac{\beta \mu}{\sigma^2} \) is equal to:
