Let \( 9 = x_1 < x_2 < \ldots < x_7 \) be in an A.P. with common difference \( d \). If the standard deviation of \( x_1, x_2, \ldots, x_7 \) is \( 4 \) and the mean is \( \bar{x} \), then \( \bar{x} + x_6 \) is equal to:
\( 25 \)
\( 2\!\left( 9 + \frac{8}{\sqrt{7}} \right) \)
\( 18\!\left(1 + \frac{1}{\sqrt{3}}\right) \)
\( 34 \)