If the mean of the following probability distribution of a random variable \( X \):
| \( X \) |
\( 0 \) |
\( 2 \) |
\( 4 \) |
\( 6 \) |
\( 8 \) |
| \( P(X) \) |
\( a \) |
\( 2a \) |
\( a + b \) |
\( 2b \) |
\( 3b \) |
is \( \dfrac{46}{9} \), then the variance of the distribution is: