If \( g(x) = 3x^2 + 2x - 3 \), \( f(0) = -3 \) and \( 4g(f(x)) = 3x^2 - 32x + 72 \), then \( f(g(2)) \) is equal to:
\( \frac{7}{2} \)
\( \frac{25}{6} \)
\( -\frac{7}{2} \)