If \( f(x)=\dfrac{(\tan 1^\circ)\,x+\log_e (123)}{x\log_e(1234)-(\tan 1^\circ)} , \; x>0 \), then the least value of \( f(f(x))+f\!\left(f\!\left(\dfrac{4}{x}\right)\right) \) is:
\( 2 \)
\( 0 \)
\( 4 \)
\( 8 \)