If \( f(x)=\frac{4x+3}{6x-4}, \, x\neq \frac{2}{3} \) and \( (fof)(x)=g(x) \), where \( g:\mathbb{R}-\left\{\frac{2}{3}\right\}\to \mathbb{R}-\left\{\frac{2}{3}\right\} \), \( (gogog)(4) \) is equal to:
\( -\frac{19}{20} \)
\( 4 \)
\( -4 \)
\( \frac{19}{20} \)