The equation of current in a purely inductive circuit is \( 5 \sin(49\pi t - 30^\circ) \). If the inductance is \( 30 \, \text{mH} \) then the equation for the voltage across the inductor, will be:{Let \( \pi = \dfrac{22}{7} \)}
\( 1.47 \sin(49\pi t - 30^\circ) \)
\( 1.47 \sin(49\pi t + 60^\circ) \)
\( 23.1 \sin(49\pi t - 30^\circ) \)
\( 23.1 \sin(49\pi t + 60^\circ) \)