An oxide of iron contains \( 69.9\% \) iron, it empirical formula, is:(Given: Molar mass of Fe and O are \( 56 \) and \( 16\,\text{g mol}^{-1} \) respectively)
\( \mathrm{FeO} \)
\( \mathrm{Fe_2O_3} \)
\( \mathrm{Fe_3O_4} \)
\( \mathrm{FeO_3} \)