Two dices are rolled. If both dices have six faces numbered \( 1, 2, 3, 5, 7 \) and \( 11 \), then the probability that the sum of the numbers on the top faces is less than or equal to \( 8 \) is:
\( \frac{5}{12} \)
\( \frac{1}{2} \)
\( \frac{4}{9} \)
\( \frac{17}{36} \)