Let \( A \) denote the event that a \( 6 \)-digit integer formed by \( 0,1,2,3,4,5,6 \) without repetitions, be divisible by \( 3 \). Then probability of event \( A \) is equal to:
\( \dfrac{11}{27} \)
\( \dfrac{3}{7} \)
\( \dfrac{4}{9} \)
\( \dfrac{9}{56} \)