The shortest distance between the lines \( \dfrac{x-1}{2}=\dfrac{y+8}{-7}=\dfrac{z-4}{5} \) and \( \dfrac{x-1}{2}=\dfrac{y-2}{1}=\dfrac{z-6}{-3} \) is:
\( 4\sqrt{3} \)
\( 5\sqrt{3} \)
\( 2\sqrt{3} \)
\( 3\sqrt{3} \)