The shortest distance between the lines \( \dfrac{x-4}{4}=\dfrac{y+2}{5}=\dfrac{z+3}{3} \) and \( \dfrac{x-1}{3}=\dfrac{y-3}{4}=\dfrac{z-4}{2} \) is:
\( 6\sqrt{3} \)
\( 6\sqrt{2} \)
\( 3\sqrt{6} \)
\( 2\sqrt{6} \)