Let the point \( (+1, \alpha, \beta) \) lie on the line of the shortest distance between the lines \( \dfrac{x + 2}{-3} = \dfrac{y - 2}{4} = \dfrac{z - 5}{2} \) and \( \dfrac{x + 2}{1} = \dfrac{y + 6}{2} = \dfrac{z - 1}{0} \).Then \( (\alpha - \beta)^{2} \) is equal to \( \_\_\_\_\_\_ \).
