Let the line \( L \) intersect the lines \( x - 2 = -y = z - 1 \), \( 2(x + 1) = 2(y - 1) = z + 1 \) and be parallel to the line \( \dfrac{x - 2}{3} = \dfrac{y - 1}{1} = \dfrac{z - 2}{2} \). Then which of the following points lies on \( L \)?
\( \left(-\dfrac{1}{3}, 1, 1\right) \)
\( \left(-\dfrac{1}{3}, -1, 1\right) \)
\( \left(-\dfrac{1}{3}, -1, -1\right) \)
\( \left(-\dfrac{1}{3}, 1, -1\right) \)
