The value of the integral \(\displaystyle\int_{-1}^{2} \log_e \left( x + \sqrt{x^2 + 1} \right) dx \) is
\( \sqrt{2}-\sqrt{5}+\log_{e}\!\left(\dfrac{7+4\sqrt{5}}{1+\sqrt{2}}\right) \)
\( \sqrt{2}-\sqrt{5}+\log_{e}\!\left(\dfrac{9+4\sqrt{5}}{1+\sqrt{2}}\right) \)
\( \sqrt{5}-\sqrt{2}+\log_{e}\!\left(\dfrac{9+4\sqrt{5}}{1+\sqrt{2}}\right) \)
\( \sqrt{5}-\sqrt{2}+\log_{e}\!\left(\dfrac{7+4\sqrt{5}}{1+\sqrt{2}}\right) \)