The integral \( \displaystyle \int_{0}^{1} \cot^{-1}(1 + x + x^{2}) \, dx \) is equal to:
\( 2\tan^{-1}2 + \dfrac{1}{2}\log_{e}\!\left(\dfrac{5}{4}\right) + \dfrac{\pi}{2} \)
\( 2\tan^{-1}2 + \dfrac{1}{2}\log_{e}\!\left(\dfrac{5}{4}\right) - \dfrac{\pi}{2} \)
\( 2\tan^{-1}2 - \dfrac{1}{2}\log_{e}\!\left(\dfrac{5}{4}\right) + \dfrac{\pi}{2} \)
\( 2\tan^{-1}2 - \dfrac{1}{2}\log_{e}\!\left(\dfrac{5}{4}\right) - \dfrac{\pi}{2} \)