The integral \( \int \frac{(2x-1)\cos\!\left(\sqrt{(2x-1)^2+5}\right)}{\sqrt{4x^2-4x+6}}\,dx \) is equal to: (where \( c \) is a constant of integration)
\( \frac{1}{2}\sin\!\left(\sqrt{(2x-1)^2+5}\right) + c \)
\( \frac{1}{2}\cos\!\left(\sqrt{(2x+1)^2+5}\right) + c \)
\( \frac{1}{2}\sin\!\left(\sqrt{(2x+1)^2+5}\right) \)
\( \frac{1}{2}\cos\!\left(\sqrt{(2x-1)^2+5}\right) \)