Let \( I(x) = \displaystyle \int \frac{(x+1)}{x(1 + x e^{x})^{2}}\,dx,\; x > 0. \) If \( \displaystyle \lim_{x \to \infty} I(x) = 0 \), then \( I(1) \) is equal to:
\( \dfrac{e+2}{e+1} + \log_{e}(e+1) \)
\( \dfrac{e+1}{e+2} + \log_{e}(e+1) \)
\( \dfrac{e+2}{e+1} - \log_{e}(e+1) \)
\( \dfrac{e+1}{e+2} - \log_{e}(e+1) \)