Let the foci of the ellipse \( \dfrac{x^{2}}{16} + \dfrac{y^{2}}{7} = 1 \) and the hyperbola \( \dfrac{x^{2}}{144} - \dfrac{y^{2}}{\alpha} = \dfrac{1}{25} \) coincide. Then the length of the latus rectum of the hyperbola is:
\( \dfrac{32}{9} \)
\( \dfrac{18}{5} \)
\( \dfrac{27}{4} \)
\( \dfrac{27}{10} \)