$\text{Consider the hyperbola } \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \text{ having one of its focus at } P(-3,0). \text{ If the latus}$ $\text{rectum through its other focus subtends a right angle at } P \text{ and } a^2b^2 = \alpha\sqrt{2} - \beta, \alpha, \beta \in \mathbb{N},$ $\text{then } \alpha + \beta \text{ is ____________ .}$
Let the sum of the focal distance of the point \( P(4,3) \) on the hyperbola \( H:\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1 \) be \( 8\sqrt{\dfrac{5}{3}} \). If for \( H \), the length of the latus rectum is \( l \) and the product of the focal distances of the point \( P \) is \( m \), then \( 9l^2+6m \) is equal to:
