If \( P(6,1) \) be the orthocentre of the triangle whose vertices are \( A(5,-2), B(8,3) \) and \( C(h,k) \), then the point \( C \) lies on the circle:
\( x^{2}+y^{2}-61=0 \)
\( x^{2}+y^{2}-74=0 \)
\( x^{2}+y^{2}-65=0 \)
\( x^{2}+y^{2}-52=0 \)