The equations of two sides \( AB \) and \( AC \) of a triangle \( ABC \) are \( 4x + y = 14 \) and \( 3x - 2y = 5 \), respectively. The point \( \left(2, \frac{4}{3}\right) \) divides the third side \( BC \) internally in the ratio \( 2:1 \), the equation of the side \( BC \) is:
