Let the mid points of the sides of a triangle \( ABC \) be \( \left(\dfrac{5}{2},7\right) \), \( \left(\dfrac{5}{2},3\right) \) and \( (4,5) \). If its incentre is \( (h,k) \), then \( 3h+k \) is equal to:
\( 11 \)
\( 12 \)
\( 13 \)
\( 14 \)