The vertices of a triangle are \( A(-1,3) \), \( B(-2,2) \) and \( C(3,-1) \). A new triangle is formed by shifting the sides of the triangle by one unit inwards. Then the equation of the side of the new triangle nearest to origin is:
\( x-y-(2+\sqrt{2})=0 \)
\( x+y-(2-\sqrt{2})=0 \)
\( -x+y-(2-\sqrt{2})=0 \)
\( x+y+(2-\sqrt{2})=0 \)
