Let \( \left(5, \frac{a}{4}\right) \) be the circumcenter of a triangle with vertices \( A(a, -2) \), \( B(a, 6) \) and \( C\!\left(\frac{a}{4}, -2\right) \). Let \( \alpha \) denote the circumradius, \( \beta \) denote the area and \( \gamma \) denote the perimeter of the triangle. Then \( \alpha + \beta + \gamma \) is:
