The distance of the point \( (2,3) \) from the line \( 2x-3y+28=0 \), measured parallel to the line \( \sqrt{3}x-y+1=0 \), is equal to:
\( 4\sqrt{2} \)
\( 4+6\sqrt{3} \)
\( 3+4\sqrt{2} \)
\( 6\sqrt{3} \)