If the center and radius of the circle \( \left|\dfrac{z-2}{z-3}\right|=2 \) are respectively \( (\alpha,\beta) \) and \( \gamma \), then \( 3(\alpha+\beta+\gamma) \) is equal to:
\( 11 \)
\( 10 \)
\( 9 \)
\( 12 \)
