If \( a_{r}=\cos \frac{2r\pi }{9}+i \sin \frac{2r\pi }{9},\ r=1,2,3,\ldots,\ i=\sqrt{-1} \), then the determinant is equal to:
\( a_{9} \)
\( a_{1}a_{9}-a_{3}a_{7} \)
\( a_{2}a_{6}-a_{4}a_{8} \)
\( a_{5} \)