If \(\displaystyle \lim_{x \to 0} \frac{3 + \alpha \sin x + \beta \cos x + \log_e(1 - x)}{3 \tan^2 x} = \frac{1}{3} \), then \( 2\alpha - \beta \) is equal to:
\( 2 \)
\( 1 \)
\( 7 \)
\( 5 \)