If \( y(x) = x^x, \, x > 0 \), then \( y''(2) - 2y'(2) \) is equal to:
\( 8 \, \log_e 2 - 2 \)
\( 4(\log_e 2)^2 + 2 \)
\( 4(\log_e 2)^2 - 2 \)
\( 4 \, \log_e 2 + 2 \)