Let \( f \) and \( g \) be twice differentiable functions on such that\( f''(x)=g''(x)+6x \)\( f'(1)=4g'(1)-3=9 \)\( f(2)=3g(2)=12 \)Then which of the following is NOT true?
\( g(-2)-f(-2)=20 \)
If $-1 < x < 2$ then, $|f(x) - g(x)| < 8$
$|f'(x) - g'(x)| < 6 \implies -1 < x < 1$
There exists \( x_{0}\in\left(1,\frac{3}{2}\right) \) such that \( f(x_{0})=g(x_{0}) \)