In a Young’s double slits experiment, the ratio of amplitude of light coming from slits is \( 2 : 1 \). The ratio of the maximum to minimum intensity in the interference pattern is :
Two slits are \( 1 \, \text{mm} \) apart and the screen is located \( 1 \, \text{m} \) away from the slits. A light of wavelength \( 500 \, \text{nm} \) is used. The width of each slit to obtain \( 10 \) maxima of the double slit pattern within the central maximum of the single slit pattern is __________ \( \times 10^{-4} \, \text{m} \)
