From the given data, the amount of energy required to break the nucleus of aluminium \( ^{27}_{13}\text{Al} \) is ______ \(x \times 10^{-3} \, \text{J} \).
Mass of neutron = \( 1.00866 \, \text{u} \)
Mass of proton = \( 1.00726 \, \text{u} \)
Mass of Aluminium nucleus = \( 27.18846 \, \text{u} \)
(Assume \( 1 \, \text{u} \) corresponds to \( x \, \text{J} \) of energy)
(Round off to the nearest integer)