The disintegration energy \( Q \) for the nuclear fission of \( {}^{235}\!U \rightarrow {}^{140}\!Ce + {}^{94}\!Zr + n \) is ____________ \( \text{MeV} \).
Given atomic masses of \( {}^{235}\!U : 235.0439 \, u \); \( {}^{140}\!Ce : 139.9054 \, u \), \( {}^{94}\!Zr : 93.9063 \, u \); \( n : 1.0086 \, u \),
Value of \( c^{2} = 931 \, \text{MeV} / u \).
