Two inclined planes are placed as shown in figure. A block is projected from the point \( A \) of inclined plane \( AB \) along its surface with a velocity just sufficient to carry it to the top point \( B \) at a height \( 10 \, \text{m} \). After reaching the Point \( B \) the block slides down on inclined plane \( BC \). Time it takes to reach to the point \( C \) from point \( A \) is \( t(\sqrt{2}+1) \, \text{s} \). The value of \( t \) is _______. (use \( g = 10 \, \text{m/s}^{2} \)).
