\( \mathrm{N_{2(g)}} + 3\mathrm{H_{2(g)}} \rightleftharpoons 2\mathrm{NH_{3(g)}} \)
\( 20 \, \text{g} \) \( 5 \, \text{g} \)
Consider the above reaction, the limiting reagent of the reaction and number of moles of \( \mathrm{NH_3} \) formed respectively are:
