If \( p, q \) and \( r \) are three propositions, then which of the following combination of truth values of \( p, q \) and \( r \) makes the logical expression \( \{(p \vee q) \wedge ((\sim p) \vee r)\} \rightarrow ((\sim q) \vee r) \) false?
\( p = F, \ q = T, \ r = F \)
\( p = T, \ q = F, \ r = T \)
\( p = T, \ q = F, \ r = F \)
\( p = T, \ q = T, \ r = F \)
