If \( \sin\!\left(\dfrac{\pi}{18}\right)\sin\!\left(\dfrac{5\pi}{18}\right)\sin\!\left(\dfrac{7\pi}{18}\right)=k \), then the value of \( \sin\!\left(\dfrac{10k\pi}{3}\right) \) is:
\( \dfrac{\sqrt{3}+1}{2\sqrt{2}} \)
\( \dfrac{\sqrt{3}-1}{\sqrt{2}} \)
\( \dfrac{\sqrt{3}}{2} \)
\( \dfrac{1}{2} \)