Let \( A = [a_{ij}]_{2 \times 2} \), where \( a_{ij} \neq 0 \) for all \( i, j \) and \( A^{2} = I \). Let \( a \) be the sum of all diagonal elements of \( A \) and \( b = |A| \). Then \( 3a^{2} + 4b^{2} \) is equal to:
\(14\)
\(4\)
\(7\)
\(3\)