, \( d = |A| \neq 0 \) and \( |A - d(\operatorname{Adj} A)| = 0 \). Then:
\( (1+d)^2 = m^2 + q^2 \)
\( (1+d)^2 = (m+q)^2 \)
\( 1 + d^2 = m^2 + q^2 \)
\( 1 + d^2 = (m+q)^2 \)