Let \( A \) be a \( 2\times 2 \) matrix with \( \det(A) = -1 \) and \( \det\!\left((A+I)\big(\operatorname{Adj}(A)+I\big)\right)=4 \). Then the sum of the diagonal elements of \( A \) can be:
\( -1 \)
\( 2 \)
\( 1 \)
\( -\sqrt{2} \)