Let for a triangle \(ABC\),
\(\overrightarrow{AB}=-2\hat{i}+\hat{j}+3\hat{k}\)
\(\overrightarrow{CB}=\alpha\hat{i}+\beta\hat{j}+\gamma\hat{k}\)
\(\overrightarrow{CA}=4\hat{i}+3\hat{j}+\delta\hat{k}\).
If \(\delta>0\) and the area of the triangle \(ABC\) is \(5\sqrt{6}\), then \(\overrightarrow{CB}\cdot\overrightarrow{CA}\) is equal to :
