If the points \( P \) and \( Q \) are respectively the circumcenter and the orthocenter of a \( \triangle ABC \), then \( \overrightarrow{PA}+\overrightarrow{PB}+\overrightarrow{PC} \) is:
\( 2\overrightarrow{QP} \)
\( \overrightarrow{QP} \)
\( 2\overrightarrow{PQ} \)
\( \overrightarrow{PQ} \)