Let \( I=\displaystyle \int\limits_{\pi/4}^{\pi/3}\left(\frac{8\sin x-\sin 2x}{x}\right)\,dx \). Then
\( \dfrac{\pi}{2} < I < \dfrac{3\pi}{4} \)
\( \dfrac{\pi}{5} < I < \dfrac{5\pi}{12} \)
\( \dfrac{5\pi}{12} < I < \dfrac{\sqrt{2}}{3}\pi \)
\( \dfrac{3\pi}{4} < I < \pi \)