Let \( f(x) \) and \( g(x) \) be twice differentiable functions satisfying \( f''(x)=g''(x) \) for all \( x\in \mathbb{R} \), \( f'(1)=2g'(1)=4 \) and \( g(2)=3f(2)=9 \). Then \( f(25)-g(25) \) is equal to:
\( 20 \)
\( 40 \)
\( -20 \)
\( -40 \)