The maximum area of a triangle whose one vertex is at \( (0, 0) \) and the other two vertices lie on the curve \( y = -2x^2 + 54 \) at points \( (x, y) \) and \( (-x, y) \), where \( y > 0 \), is:
\( 92 \)
\( 122 \)
\( 88 \)
\( 108 \)