Let \( S = \dfrac{1}{25!} + \dfrac{1}{3!23!} + \dfrac{1}{5!21!} + \ldots \) upto \( 13 \) terms. If \( 13S = \dfrac{2^{k}}{n!} ,\ k \in \mathbb{N} \), then \( n + k \) is equal to:
\( 49 \)
\( 51 \)
\( 52 \)
\( 50 \)