If the set \( \left\{\operatorname{Re}\!\left(\dfrac{z-\bar{z}+z\bar{z}}{2-3z+5\bar{z}}\right): z\in \mathbb{C}, \operatorname{Re}(z)=3 \right\} \) is equal to the interval \( (\alpha,\beta] \), then \( 24(\beta-\alpha) \) is equal to:
\( 27 \)
\( 30 \)
\( 36 \)
\( 42 \)
